To find out the required stock volum, we can use the formula
V1 C1 = V2 C2
So, to produce 1.5 L of 1 X we have to add 60 ml of stock volume with 1440 ml of water.
You need 1 liter of 1x TAE, you have a 5x stock solution. How much 5x TAE stock do you need in ml? ml How much water do you need in ml? ml
You have a 50X stock of electrophoresis buffer and you need 150ul of 1X. How do you make this happen? For Vs i got 3ul of 50X stock needed to prepare 150 ul of 1X. Then I got 147ul of h2o needed to prep 150ul of 1X. I am wondering if these are correct and if I am using the right wording with my answers? Should i be wording them in a different way? just don't want to get marked...
4) You have a 50 mM stock solution of sodium dodecylsulfate and you need to make 50 mL of a 0.1 mM solution. How much sodium dodecylsulfate will you need from the stock solution? 5) For Question #4, how much water will you need to add?
You need to make a 50X stock solution for later use. The 1X solution requires 0.9 g/100 mls final. So, to make 500 mls of 50X stock solution, how many grams will you add?
I need to make 100mL of a 50mM HCl solution. I have a 5 M stock HCl solution. How much of my 5 M HCl solution and how much water should I add to make 100mL of a 50mM HCl solution?
how much ampicillin will you need to make 5 ml of a 1000x solution? Given that the working solution (1x) is 50 ug/ml?
Imagine that you are in chemistry lab and need to make 1.00 L of a solution with a pH of 2.40. You have in front of you 100 mL of 6.00×10−2M HCl, 100 mL of 5.00×10−2M NaOH, and plenty of distilled water. You start to add HCl to a beaker of water when someone asks you a question. When you return to your dilution, you accidentally grab the wrong cylinder and add some NaOH. Once you realize your error, you...
how do you make 500ml of 1X SDS running buffer from a 5X stock solution?
calculate how much glycerol stock you would need to add to make 5ml of a 15% (v/v) glycerol solution (asssume glycerol solution is a liquid offered at 100% w/v)
Imagine that you are in chemistry lab and need to make 1.00 L of a solution with a pH of 2.40. You have in front of you 100 mL of 7.00×10−2 M HCl, 100 mL of 5.00×10−2 M NaOH, and plenty of distilled water. You start to add HCl to a beaker of water when someone asks you a question. When you return to your dilution, you accidentally grab the wrong cylinder and add some NaOH. Once you realize your...