Problem

Solutions For An Introduction to Genetic Analysis Chapter 3 Problem 47P

Step-by-Step Solution

Solution 1

A pentahybrid cross is conducted between two pentahybrids which possess the following genotypes:

A/a ; B/b ; C/c ; D/d ;E/e x a/a ; B/b ; c/c ; D/d ; e/e

a) Since all the genes assort independently, each probability is calculated and then multiplied.

1. The proportion of progeny which phenotypically resemble the first parent can be calculated in this way.

• When A/a and a/a are crossed, the probability of A will be 1/2

• When B/b and B/b are crossed, the probability of B will be 3/4

• When C/c and c/c are crossed, the probability of C will be 1/2

• When D/d and D/d are crossed, the probability of D will be 3/4

• When E/e and e/e are crossed, the probability of E will be 1/2

The total probability would be:

2. The proportion of progeny which will phenotypically resemble the second parents can be calculated in this way.

• When A/a and a/a are crossed, the probability of a will be 1/2

• When B/b and B/b are crossed, the probability of B will be 3/4

• When C/c and c/c are crossed, the probability of c will be 1/2

• When D/d and D/d are crossed, the probability of D will be 3/4

• When E/e and e/e are crossed, the probability of e will be 1/2

The total probability would be:

3. The proportion of progeny which will phenotypically resemble either parent would be the sum of the above two subparts - (1) and (2).

4. The proportion of progeny which will phenotypically resemble neither parent would be 1the result from the above subpart (3).

b) The proportion of progeny which will genotypically resemble the first parent can be calculated in this way.

1. The probability of A/a will be 1/2, B/b will be 1/2, C/c will be 1/2, D/d will be 1/2 and E/e will be 1/2.

The total probability will be:

2. The proportion of progeny which will genotypically resemble the second parent can be calculated in this way.

The probability of a/a will be 1/2, the probability of B/b will be 1/2, the probability of c/c will be 1/2, the probability of D/d will be 1/2, and the probability of e/e will be 1/2.

The total probability will be:

3. The proportion of progeny which will have the genotype of either parent would be the sum of the above subparts - (1) and (2).

4. The proportion of progeny which will have the genotype of neither parent will be 1the result of the above subpart (3).

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