Problem

Solutions For An Introduction to Genetic Analysis Chapter 3 Problem 27P

Step-by-Step Solution

Solution 1

The above results show that the absence of trichomes is caused by a recessive allele in both mutants. By observing, the F2 results showed 3:1 ratio. Taking A as normal and a as mutant, the proposed genotypes of all the plants would be:

1- A/A: Normal

2- A/a: Normal

1- a/a: mutated phenotype with no trichomes

Step #2 of 3

The genotypic ratio is 1:2:1

Step #3 of 3

The original mutant A is crossed with the original mutant B to produce F1. The F1 is testcrossed with a homozygous recessive plant (aabb). The crossing is shown in below diagram:

1: AaBb – Normal Phenotype

1: Aabb – mutant phenotype, no trichomes

1: aaBb – mutant phenotype, no trichomes

1: aabb – mutant phenotype, no trichomes

The proportion of testcross progeny with no trichomes would be 3:1.

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