Problem

Solutions For An Introduction to Genetic Analysis Chapter 3 Problem 28P

Step-by-Step Solution

Solution 1

The genes that determine coat color are as follows:

• Dark = C

• Albino = c

The Dark (C) is dominant over Albino (c). Thus, the genotypes, which express Dark and Albino phenotype, are as follows:

Dark:

CC- Homozygous dominant

Cc- Heterozygous dominant

Albino:

cc- Homozygous recessive

The genes that determine Hair length are as follows:

• Short = H

• Long = h

The Short (H) is dominant over Long (h). Thus, the genotypes, which express Short and Long phenotype, are as follows:

Short:

HH- Homozygous dominant

Hh- Heterozygous dominant

Long:

hh- Homozygous recessive

The seven mating’s with the above phenotypes give following number of progeny.

Mating

Parental phenotypes

Number of progeny (%)

Dark, Short

Dark, Long

Albino, Short

Albino, Long

a.

Dark, Short × Dark, Short

55

19.375

18.125

7.5

b.

Dark, Short × Dark, Long

51.4

48.6

0

0

c.

Dark, Short × Albino, Short

51.2

0

48.8

0

d.

Albino, Short × Albino, Short

0

0

76.3

23.7

e.

Dark, Long× Dark, Long

0

73.8

0

26.2

f.

Dark, Short × Dark, Short

73.8

26.2

0

0

g.

Dark, Short × Dark, Long

38.3

37.0

12.3

12.3

The genotypes, which shows

• Dark, Short: CCHH, CCHh, CcHH and CcHh

• Dark, Long: CChh and Cchh

• Albino, Short: ccHH and ccHh

• Albino, long: cchh

The cross of “mating-a” (Dark, Short × Dark, Short) is as follows:

Picture 1

Thus, the probable genotypes of parents for mating-a, are as follows: CcHh × CcHh.

The cross of “mating-b” (Dark, Short × Dark, Long) is as follows:

Picture 3

Thus, the probable genotypes of parents for mating-b, are as follows: CCHh × Cchh.

The cross of “mating-c” (Dark, Short × Albino, Short) is as follows:

Picture 4

Thus, the probable genotypes of parents for mating-c, are as follows: CcHH × ccHH.

The cross of “mating-d” (Albino, Short × Albino, Short) is as follows:

Picture 5

Thus, the probable genotypes of parents for mating-d, are as follows: ccHh × ccHh.

The cross of “mating-e” (Dark, Long× Dark, Long) is as follows:

Picture 9

Thus, the probable genotypes of parents for mating-e are as follows: Cchh × Cchh.

The cross of “mating-f” (Dark, Short × Dark, Short) is as follows:

Picture 7

Thus, the probable genotypes of parents for mating-f are as follows: CCHh × CcHh.

The cross of “mating-g” (Dark, Short × Dark, Long) is as follows:

Picture 8

Thus, the probable genotypes of parents for mating-g are as follows: CcHh × Cchh.

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