Problem

Solutions For An Introduction to Genetic Analysis Chapter 3 Problem 29P

Step-by-Step Solution

Solution 1

The genes that determine stem color in tomatoes are as follows:

• Purple Stem = G

• Green stem = g

The genes that determine leaf shape in tomatoes are as follows:

• Cut = P

• Potato = p

The five mating’s of the tomato plants with the above phenotypes give following number of progeny.

Mating

Parental phenotypes

Number of progeny

Purple and Cut

Purple and Potato

Green and Cut

Green and Potato

1

Purple and Cut × Green and Cut

323

102

309

106

2

Purple and Cut × Purple and Potato

220

206

65

72

3

Purple and Cut × Green and Cut

732

229

0

0

4

Purple and Cut × Green and Potato

405

0

389

0

5

Purple and Potato × Green and Potato

71

90

85

78

a.

From the above data, all most all the mating’s have 1:1:1:1 ratio. So, these crosses may be either a test cross or a back cross.

If one can see the number of progeny form mating 1 and mating 2, the mating-1 shows that Cut (P) has more progeny than Potato (p). Thus, the P is dominant over p or P >p.

• The genotypes that express Cut (P) phenotype: PP and Pp

• The genotype that express Potato (p) phenotype: pp

The mating-2 shows that Purple (G) has more progeny than Green (g). Thus, the G is dominant over g or G >g.

• The genotypes that express Purple (G) phenotype: GG and Gg

• The genotypes that express Green (g) phenotype: gg

b.

The probable genotypes of parents of the each cross are as follows: Mating-1: It expresses an equal number of all phenotypes (Purple and Cut × Green and Cut).

Picture 1

Thus, the probable genotypes of parents for mating 1 are GgPp × ggPp.

Mating-2: It expresses equal number of all phenotypes (Purple and Cut × Purple and Potato).

Picture 2

Thus, the probable genotypes of parents for mating 2 are GgPp × Ggpp.

Mating-3: In this cross there is no phenotype with Green stem (Purple and Cut × Green and Cut).

Picture 5

From the above cross the obtained phenotypes are as follows:

• 75% of Purple and Cut

• 25% of Purple and Potato

Thus, the probable genotypes of parents for mating 2 are GGPp × ggPp.

Mating-4: In this cross there is no phenotype with potato (Purple and Cut × Green and Potato).

Picture 4

From the above cross the obtained phenotypes are as follows:

• 50% of Purple and Cut

• 50% of Green and Cut

Thus, the probable genotypes of parents for mating 2 are GgPP × ggpp.

Mating-5: It expresses equal number of all phenotypes (Purple and Potato × Green and Potato).

Picture 6

Thus, the probable genotypes of parents for mating 2 are Ggpp × ggPp.

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