Problem

Solutions For An Introduction to Genetic Analysis Chapter 3 Problem 49P

Step-by-Step Solution

Solution 1

The genotypes of three pure lines of corn plants bred by a geneticist are:

• a/a ; B/B ; C/C

A/A ; b/b ; C/C

A/A ; B/B ; c/c

The geneticist wants to combine the 3 genes of a, b, and c as a pure line.

a) An effective crossing program, which can be used to gain a pure line of a/a; b/b; c/c would be:

• Cross any of the two plants given above to get progeny. The progeny is selfed.

• We get 1/16th of the progeny with two of the desired genes in a homozygous state.

• This progeny is then crossed with the third plant from the above list getting a triple heterozygous plant.

• This triple heterozygote is then selfed to obtain the desired genotype as 1/64th of the progeny.

b) The phenotypes and the frequencies for each stage can be given in the following way:

• The plant a/a; B/B ; C/C is crossed with A/A; b/b; C/C giving the progeny of A/a; B/b; C/C. Selfing of this plant will give the following progeny:

9:3:3:1

9 – A/- ; B/- ; C/C

3 – a/a; B/- ; C/C

3 – A/- ; b/b; C/C

1 – a/a; b/b; C/C

• Only 1/16th of the progeny has a/a; b/b; C/C with two of the desired genes in a homozygous state.

• This plant a/a; b/b; C/C is then crossed with A/A; B/B; c/c to give a triple heterozygous plant – A/a; B/b; C/c.

• This triple heterozygote is then selfed to obtain the ratio of 27:9:9:9:3:3:3:1. The desired genotype of a/a; b/b; c/c occurs as 1/64th of the progeny.

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