Problem

Solutions For An Introduction to Genetic Analysis Chapter 3 Problem 12P

Step-by-Step Solution

Solution 1

Taking a plant A/a; B/b, by assuming the principle of independent assortment, we can find out the phenotypic and genotypic ratios associated with it.

a) When the plant A/a; B/b is selfed, the phenotypic ratio produced from such a cross would be:

The phenotypic ratio would be: 9:3:3:1

• 9 – A/; B/-

• 3 - A/- ; b/b

• 3 – a/a; B/-

• 1 - a/a; b/b

Step #2 of 4

b) When the plant A/a; B/b is selfed, the genotypic ratio produced from such a cross would be:

The genotypic ratio would be 1:2:2:4:1:2:1:2:1

• 1 - AABB

• 2 - AABb

• 2 - AaBB

• 4 - AaBb

• 1 - AAbb

• 2 - Aabb

• 1 - aaBB

• 2 - aaBb

• 1 – aabb

Step #3 of 4

c) When the plant A/a; B/b is test crossed, we use a completely recessive plant (a/a;b/b). The phenotypic ratio produced would be:

The phenotypic ratio would be 1:1:1:1

• 1 – AaBb

• 1 – Aabb

• 1 – aaBb

• 1 – aabb

Step #4 of 4

d) When the plant A/a; B/b is test crossed, we use a completely recessive plant (a/a;b/b). The genotypic ratio produced would be:

The genotypic ratio would be 1:1:1:1

• 1 – AaBb

• 1 – Aabb

• 1 – aaBb

• 1 – aabb

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Solutions For Problems in Chapter 3

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