Problem

For the reaction A + B → C + D, a run with [A]0 = 400 mmol dm−3 and [B]0 = 0.400 mmol dm−3...

For the reaction A + B → C + D, a run with [A]0 = 400 mmol dm−3 and [B]0 = 0.400 mmol dm−3 gave the following data (where c° nu≡ 1 mol/dm3):

t/s

0

120

240

360

104[C]/c°

0

2.00

3.00

3.50

4.00

and a run with [A]0 = 0.400 mmol dm−3 and [B]0 = 1000 mmol dm−3 gave

10 −3 t/s

0

69

208

485

104[C]/c°

0

2.00

3.00

3.50

4.00

Find the rate law and the rate constant. The numbers have been chosen to make determination of the orders simple.

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