The table showing the chromosome constitutions in a normally diploid organism with three chromosomes is shown below:
| Name | Designation | Constitution | No. of chromosomes |
| Euploids | |||
| Monoploid | n | A B C | 3 |
| Diploid | 2n | AA BB CC | 6 |
| Triploid | 3n | AAA BBB CCC | 9 |
| Tetraploid | 4n | AAAA BBBB CCCC | 12 |
| Aneuploids | |||
| Monosomic | 2n – 1 | A BB CC | 5 |
| AA B CC | 5 | ||
| AA BB C | 5 | ||
| Trisomic | 2n +1 | AAA BB CC | 7 |
| AA BBB CC | 7 | ||
| AA BB CCC | 7 |
Based on the above table we can characterize the following genomes:
HH II J KK:
This would be monosomic as a single chromosome of J is missing.
HH II JJ KKK:
This would be trisomic since an extra K chromosome is present. This is an aneuploid.
HHHH IIII JJJJ KKKK:
This would be tetraploid since all the four different types of chromosomes have four copies each. This is a euploid.