Step-by-Step Solution
Solution 1
A fruit fly of genotype 
is crossed with a homozygous recessive organism 
in a testcross. In 84% of the meioses, no chiasmata are seen in linked genes. In the remaining 16% of meioses, one chiasma is seen between the genes.
Since, one chiasma involves only two of the four chromatids, 16% of meioses will indicate an 8% recombinant frequency.
Since 
is one of the two recombinants, it will be 50% of the recombination frequency, that is, 4%. The other 4% will be another recombinant 
Thus, only 
of the progeny will be
.
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