Solutions For An Introduction to Genetic Analysis Chapter 4 Problem 51P

The genes al-2 and arg-6 are 30 m.u. apart on chromosome 1 in a haploid fungus. The genes lys-5 and met-1 are 20 m.u. apart on chromosome 6. The details of the cross are as follows:

al-2 + ; + met-1 x +arg-6; lys-5 +

The transient diploid would be al-2 +/+arg-6; met-1/lys-5 +. One half of the recombinant chromosome 1 will be + + and one half of the recombinant chromosome 6 will be + +.

Since both are different chromosomes and are independent events, the percent of progeny that would be phototrophic + +; ++ can be calculated in the following way:

Therefore, the percent of progeny that would be phototrophic + +; ++ is 1.5%.