Solutions For An Introduction to Genetic Analysis Chapter 2 Problem 66P

b. Cross between orange female and black male is

Parents --X^b/X^b × X^B/Y

F1 generation X^B/X^b (female with calico)

X^b/Y (male with orange)

c. In a particular mating, the offspring are:

Half the females are calico, half are black, half of the males are orange and the other half males are black. The mother should be calico to get the male offspring orange and black. The father should be black to get half of the daughters black.

Mother-calico X^B/X^b × X^B/Y father-black

The progeny are X^B/X^B – daughter black

X ^B /X ^b- daughter calico

X ^B /Y-son black

X ^b /Y- son orange

In the progeny, half of the daughters are black and half of the daughters are calico. Among the sons half of the sons are black and half of them are orange.

d. The males are orange and black that means the mother must be calico. The daughters are orange and calico that means the father should be orange.

Mother-calico X^B/X^b × X^b/Y father orange

Progeny -> X^B/X^b female’s calico 1/4

X ^b /X ^b females orange 1/4

X ^B /Y males black 1/4

X ^b /Y males orange 1/4