Solutions For An Introduction to Genetic Analysis Chapter 2 Problem 40P

a. From the clues and data given about plant A and B, we are able to know that both A and B are homozygous recessive alleles.

Each A and B is crossed with wild-type and F₁ generation had normal trichomes.

When F₁ plants are self-crossed, F₂ generation from mutant A gives 3:1 ratio for normal to mutant and F₂ generation from mutant B gives 3:1 ratio for normal to mutant.

The genotype of all the plants is as follows:

Parents – mutant plant - a/a crossed with wild type A/A -

F₁ generation - A/a

F₁ plants are self-crossed

F₂ generation - AA, Aa, Aa, aa

1 normal phenotype AA

2 normal phenotypes Aa

1 mutant phenotype aa (no trichomes)