Solutions For An Introduction to Genetic Analysis Chapter 9 Problem 48P

631190-9-48P AID: 2498 | 23/12/2015

The three possible exon combinations that give the correct number of nucleotides without having any missing codons are as follows:

Combination 1:

Exons 1, 3, and 5

= 270 + 330 + 150

= 750 nucleotides

Each amino acid is encoded by a triplet codon

So, the number of amino acids produced

= 750/3

= 250 amino acids

Combination 2:

Exons 1, 2, and 4

= 270 + 100 + 83

= 453 nucleotides

So, the number of amino acids produced

= 453/3

= 151 amino acids

Combination 3:

Exons 1, 2, 4 and 5

= 270 + 100 + 83 + 150

= 603 nucleotides

So, the number of amino acids produced

= 603/3

= 201 amino acids