a) The proportion and identity of amino acids that will be incorporated into proteins when the mRNA (messenger ribonucleic acid) containing the bases in the given ratio (1 U:5 C) as follows: The proportion of U is 1/6 and for C is 5/6.
| Codon | Amino acid | Probability | Sum |
| UUU | Phenylalanine | (1/6) (1/6) (1/6) = 0.005 | Phe = 0.028 |
| UUC | Phenylalanine | (1/6) (1/6) (5/6) = 0.023 | |
| CCC | Proline | (5/6) (5/6) (5/6) = 0.578 | Pro = 0.694 |
| CCU | Proline | (5/6) (5/6) (1/6) = 0.116 | |
| UCC | Serine | (1/6) (5/6) (5/6) = 0.116 | Ser = 0.139 |
| UCU | Serine | (1/6) (5/6) (1/6) = 0.023 | |
| CUC | Leucine | (5/6) (1/6) (5/6) = 0.116 | Leu = 0.139 |
| CUU | Leucine | (5/6) (1/6) (1/6) = 0.023 |
1 Phe : 25 Pro: 5 Ser : 5 Leu
b) The proportion and identity of amino acids that will be incorporated into proteins when the mRNA (messenger ribonucleic acid) containing the bases in the given ratio (1 A:1 C:4 U’s) as follows:
With the same procedure as above, the concluding answer is 4 stop: 80 Phe: 40 Leu: 24 Ile : 24 Ser : 20 Tyr : 6 pro : 6 Thr : 5 Asn : 5 His : 1 Lys : 1 Gln.
c) The proportion and identity of amino acids that will be incorporated into proteins when the mRNA (messenger ribonucleic acid) containing the bases in the given ratio (1 A:1 C:1 G:1 U)) as follows: As seen in the code table all amino acids are found in the proportions.